(^{226}_{88}Ra) → (^x_{86}Rn) + alpha particle
-
A.
226 -
B.
220 -
C.
227 -
D.
222
Correct Answer: Option D
Explanation
(^{226}_{88}Ra) → (^x_{86}Rn) + (^4_{2}He)
(^4_{2}He) = alpha particle
considering the summation of the mass number
226 = x + 4
x = 226 – 4
x = 222
There is an explanation video available below.