Calculate the amount in moles of silver deposited when 9650C of electricty is passed through a solution of silver salt [= 96500 Cmol-1]
-
A.
0.05 -
B.
10.80 -
C.
10.00 -
D.
0.10
Correct Answer: Option D
Explanation
m = (frac{Mm times Q}{96500n
})
where Q = IT
M = Mm × (frac{Q}{96500n})
where m = mass
Mm = Molar mass
Q = Quantity of electricity
n = number of change= +1
(frac{M}{Mm}) = mole = (frac{mass}{Molarmass})
(frac{M}{Mm}) = (frac{Q}{96500n})
= (frac{9650}{96500n}) × 1
= (frac{1}{10}) = 0.1mol
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