What weight of NaCl is needed to make 2.0 dm3 of a 1.5M solution? [Na…

What weight of NaCl is needed to make 2.0 dm³ of a 1.5M solution?
[Na = 23, Cl = 35.5]

Correct Answer: Option B

Explanation

Molar mass of Nacl = 23 + 35.5 = 58.5 g/mol
Number of moles of Nacl = conc. in mol/dm³
x vol. in dm³
= 1.5 * 2.0 = 3.0 moles
1 mole of NaCl has a weight of 58.5 * 3
= 175.5g