The volume occupied by 0.4 g of hydrogen gas at s.t.p. is [H = 1. 00; Molar volume at s.t.p. = 22.4 dm3]
-
A.
2.24 dm3 -
B.
4.48dm3 -
C.
22.4dm3 -
D.
44.8dm 3
Correct Answer: Option B
Explanation
2g of H(_2) = 22.4 dm(^3)
0.4g of H(_2) = x,
x = (frac{0.4 times 22.4}{2}) = 4.48dm(^3)