The solubility in mol dm/-3 of 20g of CuSO4 dissolved in 100g of water at 180o is
[Cu = 64, S = 32, O =16]
[Cu = 64, S = 32, O =16]
-
A.
0.13 -
B.
0.25 -
C.
1.25 -
D.
2.00
Correct Answer: Option C
Explanation
Relative molecular mass of CuSO4 = 64 + 32 + 16 * 4 = 160
The number of moles of CUSO4 = reacting mass/molecular mass = 20/180 = 0.125
100g of water dissolved 0.125m of CuSO4
100g of water will dissolve (0.125 * 1000)/100 = 1.25mol dm3