The number of oxygen molecules present in 16.0g of the gas is____?
[Avogadro’s number = 6.02 x 1023]
[Avogadro’s number = 6.02 x 1023]
- A.
6.02 x 1022 - B.
6.02 x 1023 - C.
3.01 x 1023 - D.
1.51 x 1023
Correct Answer: Option C
Explanation
1 mole = Molar mass of gas = Avogadros number
32g of O2 = 6.02 x 1023
16g of O2 = x
x = (frac{16 times 6.02 times 10^23}{32}) = 3.01 x 1023