The number of molecules of Carbon(iv)Oxide produced when 10.0g of CaCO(_3) is treated with 0.2dm(^3) of 1 Mole of HCL in the equation
CaCO(_3) + 2HCL ⇒ CaCl(_2) + H(_2) O + CO(_2) , is ?
-
A.
1.00 X 10(^{23}) -
B.
6.02 X 10(^{23}) -
C.
6.02 X 10(^{22}) -
D.
6.02 X 10(^{24})
Correct Answer: Option C
Explanation
There is an explanation video available below.