The mass of one mole of ((NH_{4})_{2}CO_{3}) is [O=16.0, N=14.0, C=12.0, H=1.0]
-
A.
66.0g -
B.
76.0g -
C.
80.0g -
D.
96.0g
Correct Answer: Option D
Explanation
This is same as asking for the molar mass of the compound
= ((2times 14.0)+ (8times 1.0) + 12.0+(16.0times 3))
= 28.0+8.0+12.0+48.0 = 96.0g