The hydrogen ion concentration of a sample of orange juice is 2.0 X 10(^{-11})moldm(^{-3}). What is its p(^{OH})? [log102 = 0.3010]
-
A.
3.30 -
B.
13.00 -
C.
10.70 -
D.
11.30
Correct Answer: Option A
Explanation
p(^{OH}) = -Log [OH(^-)]
[OH(^-) ] = 2.0 X 10(^{-11})moldm(^{-3})
p(^{OH}) = -Log [2.0 X 10(^{-11})]
p(^{OH}) = 10.70
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