The electronic configuration of element Z is 1s(^2) 2s(^2) 2p(^6) 3s(^2) 3p(^1). What is the formula of the compound formed between Z and tetraoxosulphate (VI) ion.
-
A.
Z(_3)(SO(_4))(_2) -
B.
ZSO(_4) -
C.
Z(_2) SO(_4) -
D.
Z(_2)(SO(_4))(_3)
Correct Answer: Option D
Explanation
Z = 1s(^2) 2s(^2) 2p(^6) 3s(^2) 3p(^1)
(therefore) We have Z(^{3+}) and SO(_4 ^{2-})
The reaction : Z(^{3+}) + SO(_4 ^{2-}) (to) Z(_2)(SO(_4))(_3).
There is an explanation video available below.