RS(aq) + HF(aq) → RF(s) + HS(aq)
ΔH = -65.7 kj mol(-1).
From the equation above, it can be deduced that
ΔH = -65.7 kj mol(-1).
From the equation above, it can be deduced that
-
A.
the heat content of the reactants is lower than that of the products -
B.
the heat content of the reactants is higher than that of the products -
C.
the reaction is slow -
D.
a large amount of heat is absorbed