In the reaction between sodium hydroxide and sulphuric acid solutions, what volume of 0.5 molar sodium hydroxide would exactly neutralise 10cm3 of 1.25 molar sulphuric acid?
-
A.
5cm3 -
B.
10cm3 -
C.
20cm3 -
D.
25cm3 -
E.
50cm3
Correct Answer: Option E
Explanation
(2NaOH + H_{2}SO_{4} = Na_{2}SO_{4} + 2H_{2}O)
V x 0.5M = 2(10 x 1.25)
0.5V = 2 x 12.5
0.5V = 25
V = (frac{25}{0.5}) = (50cm^{3})