If the quantity of oxygen occupying 2.76L container at a pressure of 0.825 atm and…

If the quantity of oxygen occupying 2.76L container at a pressure of 0.825 atm and 300k is reduced by one-half, what is the pressure exerted by the remaining gas?

Correct Answer: Option A

Explanation

Using the combined gas law formula,

Given that P(_1) = 0.825,   V(_1) = 2.76 L, V(_2) = 1.38 L, P(_2) = ?

And T1 = T2; we would have P(_2) = [ P(_1) X V(_1) ] ÷ V(_2)

: [0.825 X 2.76]  ÷ 1.38

= 1.650atm

 

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