Consider the following half-cell reactions.
Al(s) (to) Al3+(aq) + 3e–
Cu2+(aq) + 2e– (to) Cu(s)
The overall equation for the reaction is
Al(s) (to) Al3+(aq) + 3e–
Cu2+(aq) + 2e– (to) Cu(s)
The overall equation for the reaction is
-
A.
Al(s) + Cu2+(aq) (to) Al3+(aq) + Cu(s) -
B.
2Al(s) + Cu2+(aq) (to) 2Al(aq) + Cu(s) -
C.
2Al(s) + 3Cu2+(aq) (to) 3Cu(s) + 2Al3+(aq) -
D.
3Al(s) + 2Cu2+(aq) (to) Cu(s) + 3Al3+(aq)
Correct Answer: Option C
Explanation
Al(s) (to) Al3+(aq) + 3e–____(i)
Cu2+(aq) + 2e– (to) Cu(s) (ii)
To balance the electrons, multiply equation (i) by 2 and equation (ii) by 3 and then add the resulting equations
2Al(s) (to)2Al3+(aq) + 3e–
3cu2+(aq) + 6e– (to)3Cu(s)
2Al(s) + 3Cu2+(aq) (to) 3Cu(s) + 2Al3+(aq)