An organic compound contains 72% carbon, 12% hydrogen and 16% oxygen by mass. The empirical formula of the compound is
-
A.
C8H22O3 -
B.
C6H10O3 -
C.
C12H12O -
D.
C6H12O -
E.
C3H6O
Correct Answer: Option D
Explanation
carbon = 72%, hydrogen = 12%, 16%
Dividing by the atomic weight we have for C = (frac{5}{1}) = 6
H = (frac{12}{1}) = 12
O = (frac{16}{16}) = 1
Divide by the smallest number, we have = (frac{6}{1}) = 6
H = (frac{12}{1}) = 12
O = (frac{1}{1}) = 1
The formula is C6H12O