A given mass of gas occupies 2dm3 at 300k. At what temperature will its volume be doubled, keeping the pressure constant?
-
A.
400k -
B.
480k -
C.
550k -
D.
600k
Correct Answer: Option D
Explanation
At constant pressure connotes Charle’s law
(frac{V_1}{T_1}) = (frac{V_2}{T_2})
(frac{2dm^3}{300k}) = 2 x (frac{2dm^3}{T_2})
T2= 600k
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