A certain volume of gas at 298k is heated such that its volume and pressure are now four times the original values. What is the new temperature?
-
A.
18.6k -
B.
100.0k -
C.
298.0k -
D.
1192.0k -
E.
4768.0k
Correct Answer: Option E
Explanation
(frac{P_1V_1}{T_1} = frac{4P_1 times 4V_1}{T_2})
i.e (frac{P_1V_1}{298} = frac{4P_1 times 4V_1}{T_2})
T2 = (frac{298 times 4P_1 times 4V_1}{P_1V_1})
= 298 + 16 = 4768.0k